(3/2b-1)+(b^2+2/1-4b^2)+b

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Solution for (3/2b-1)+(b^2+2/1-4b^2)+b equation: 


b in (-oo:+oo)

b^2-(4*b^2)+(3/2)*b+b+2/1-1 = 0

b^2-4*b^2+(3/2)*b+b-1+2 = 0

5/2*b-3*b^2+1 = 0

DELTA = (5/2)^2-(-3*1*4)

DELTA = 73/4

DELTA > 0

b = ((73/4)^(1/2)-5/2)/(-3*2) or b = (-(73/4)^(1/2)-5/2)/(-3*2)

b = ((73/4)^(1/2)-5/2)/(-6) or b = ((73/4)^(1/2)+5/2)/6

b in { ((73/4)^(1/2)-5/2)/(-6), ((73/4)^(1/2)+5/2)/6 }

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